Increasing longest sub array
We
can solve it by using:
Brute
force – Time Complexity O(n^2)
Dynamic
programming - Time Complexity O(n).
Pseudo code:
def
DP(a[]):
dp[1] = 1
for i = 2 to n:
if a[i] > a[i - 1]:
dp[i] = dp[i - 1] + 1
else:
dp[i] = 1
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